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Mathematics 6 Online
OpenStudy (anonymous):

help please:( picture posted below

OpenStudy (anonymous):

OpenStudy (austinl):

Set the equation equal to 50 and solve for t. I am gonna guess that quadratic formula will be used. :)

OpenStudy (anonymous):

can u help me?

OpenStudy (austinl):

Sure. We have the equation for height above ground as, \(s(t)=-16t^2+70t+3\) We want to know at what time will \(s(t)=50\). So we simply set it equal to 50 and solve for t. \(50=-16t^2+70t+3\) We will want to subtract 50 from both sides. \(-16t^2+70t-47=0\) Now do you think you could solve it from there?

OpenStudy (anonymous):

im not sure.. what do u do with the t's?

OpenStudy (austinl):

You solve for them :P

OpenStudy (anonymous):

lol how?

OpenStudy (austinl):

Are you familiar with the quadratic formula?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

can u please help me?

OpenStudy (austinl):

The quadratic formula is, \(\displaystyle t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\) Where, \(0=-at^2+bt-c\)

OpenStudy (anonymous):

sooo.. what would the answer be?

OpenStudy (anonymous):

@austinL ?

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