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OpenStudy (anonymous):
OpenStudy (austinl):
Set the equation equal to 50 and solve for t. I am gonna guess that quadratic formula will be used. :)
OpenStudy (anonymous):
can u help me?
OpenStudy (austinl):
Sure.
We have the equation for height above ground as,
\(s(t)=-16t^2+70t+3\)
We want to know at what time will \(s(t)=50\).
So we simply set it equal to 50 and solve for t.
\(50=-16t^2+70t+3\)
We will want to subtract 50 from both sides.
\(-16t^2+70t-47=0\)
Now do you think you could solve it from there?
OpenStudy (anonymous):
im not sure.. what do u do with the t's?
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OpenStudy (austinl):
You solve for them :P
OpenStudy (anonymous):
lol how?
OpenStudy (austinl):
Are you familiar with the quadratic formula?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
can u please help me?
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OpenStudy (austinl):
The quadratic formula is,
\(\displaystyle t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
Where,
\(0=-at^2+bt-c\)