Find F'(X) for F(x)=x^2-x
Take each term and differentiate. Derivative of x^n = n * x^(n - 1)
are you sure?
i thought you use the lim as h approaches 0 f(x+h)-f(x)/h
F'(x), y' all mean find the first derivative. y' is same as dy/dx
yes i know
If you know why are you hesitating taking the derivative?
2x-1
You guys are complicating the answers
not really, i know what the answer is but i get stick on one part of it
@math&ing001 You guide people to do the work and find the answers themselves instead of you doing the homework for others. How ill they learn with your method?
If they ask about the method you tell them then
What part are you stuck on?
umm i get stuck on the part where i factor so (x+h)^2-x-(x^2-x)/h
[(x+h)^2-x^2]/h=[(x+h-x)*(x+h+x)]=[h*(2x+h)]/h -> 2x
When you are at the stage of calculus where they have only taught you limits and not yet derivatives then you have to do the problem the long way: find the limit as h approaches 0 f(x+h) - f(x) / h. But if you already know derivatives then you can just differentiate each term. It all depends on what stage you are at.
okay i got the 2x but where does the -1 come from
From the second part -x
so why exactly is it -x?
Same method
[-(x+h)-(-x)]/h=-h/h=-1
ohh okay i see now thank you :)
Your welcome :)
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