A researcher studying the nutritional value of a new candy places a 3.00-gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.12 °C. If the heat capacity of the calorimeter is 31.70 kJ·K–1, how many nutritional Calories are there per gram of the candy?

Question

anonymous · Answer

T increase=275.3 Kelvin. E total=(31.7 *10^3)J/K *(275.3K)......Then divide this number by 3 grams to get Joules/gram. Then use conversion factor 1J=.239 calories to covert to calories per gram.

anonymous · Answer

excuse me i meant delta t=2.12 not 273

anonymous · Answer

not 275 i mean. i added 273 to convert to kelvin in haste. but we know that delta T kelvin= delta T Celsius so just keep it 2.12 :)

anonymous · Answer

so i get about 5353 cal/gram.

anonymous · Answer

thank you!!!