Question

find f'(x) of f(x)= 2x^3+1

Answer 1

use the rule

f(x) = ax^n then f'(x) = anx^(n-1)

Answer 2

well i have to show work using the lim of h as it approaches zero F(x+h)-F(x)/h

Answer 3

lim h--> 0 of f(x) = 2(x+h)^3 + 1 - (2x^3 + 1) / h
= [2x^3 + 6x^2h + 6h^2x + 2h^3 + 1 - 2x^3 - 1] / h
= [ 6x^2h + 6h^2x + 2h^3 ] / h
= 6x^2 + 6hx + 2h^2
as h ---> 6x ^2 + 6hx + 2h^2 ---> 6x^2

lim h ---> of f(x) = 6x^2

Answer 4

* correction: lim h ----> 0 ( last line)

Answer 5

* also 5th line

Answer 6

what did you do on the second line?

Answer 7

factor? or distribute?

Answer 8

distribute

Answer 9

distributed 2(x+ h)^3

Answer 10

hmmm okay i see

Answer 11

thank you very much :)

Answer 12

yw

Answer 13

close the question if it has been answered.