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Evaluate the limit using L'Hospital's rule if necessary limit (1+3/x)^(x/7) x->inf
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@ranga
it isn't necessary. plug in infinity
how did you figure that it isn't necessary?
you use l'hopital's only if you have 0^0 , inf^inf , 0/0 or inf/inf plugging in inf gives 1^inf = 1
i thought the l'hopital's need to be used if it's also 1^inf.. and i plugged the answer 1^inf, and the system marked it wrong
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answer is just 1
^inf is redundant
i also did put in 1, but it says it's wrong
Ln((1+3/x)^(x/7))= x/7*Ln(1+x/3) L'hopital use f(x)=Ln(1+3/x) and g(x)=7/x as functions they both ->0 You'll get lim f(x)/g(x)= lim f'(x)/g'(x)= 3/7 So lim (1+3/x)^(x/7) = exp(3/7)
my bad
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rip that medal off my neck
That's okay
Thanks
yw
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