Question

sinx(tan^2x)(1-sin^2x)

Answer 1

What's the question?

Answer 2

simplify the expression

Answer 3

OK

Answer 4

\[\Large sinx(\tan^2x)(1-\sin^2x)\] Our original equation

Do you know any trig identities?

Answer 5

Yeah but I'm mixing them up :/

Answer 6

Ok it's ok, we'll start with a simple one that relates to this equation, you're familar with
\[\Large \cos ^{2}(x)+\sin ^{2}(x)=1\]
yes?

Answer 7

yep!

Answer 8

Well get the cos^2(x) by itself in that equation I just provided

Answer 9

1-sin^2(x)

Answer 10

Ok and so now you can replace that into your equation

Answer 11

Next question, can you rewrite tan in terms of sin and cos, in other words what is the tan really using the sin and cos?

Answer 12

isn't that with just tanx=(sinx/cosx)? or does tan^2(x)= ((sin^2(x))/(cos^2(x))?

Answer 13

yes

Answer 14

Yes you are correct @love4bizarre , our jo here is to guide someone to the solution rather than just give it up @Loser66 , it's just a heads up I've seen people get banned like that

Answer 15

\[\Huge \tan ^{2}(x)=\frac{\sin^{2}(x)}{\cos^{2}(x)}\]

Answer 16

So basically the new equation is \[\Large sinx \times(\frac{ \sin^2(x) }{ \cos^2(x) })\times(\cos^{2}(x)) \]

Answer 17

Now you just simplify what you can and multiply the rest. Tell me what you get.

Answer 18

I got sin^3(x)

Answer 19

is that okay?

Answer 20

Yep!, you got it!

Answer 21

Thank you for explaining it so well :)