Question

Please help me with this question. :D

Answer 1

\[\log_{10} A=a\]
\[\log_{10} B=b\]

Answer 2

\[\log_{10} (A^3/\sqrt{B})\]

Answer 3

First use the log law log(x / y) = log x - log y

Answer 4

\[\log_{10} (A^3)-\log_{10} (\sqrt{B})\]

Answer 5

Now use the rule log(x^a) = a logx on both terms

remember a square root is the same as B^(1/2)

Answer 6

\[3\log_{10} (A)-1/2\log_{10} (B)\]

Answer 7

sorry that took so long. I got confused. :P

Answer 8

no you've got it now :) now...logA = a and logB = b, so finish off :)

Answer 9

btw you don't have to write the base 10. Log with no base is assumed to be 10.

Answer 10

ohh that makes sense. xD
would it just be 3a-1/2b?

Answer 11

Yep!