Ask your own question, for FREE!
Chemistry 7 Online
OpenStudy (anonymous):

for the reaction RX +OH(-) --> ROH + X(-) the rate of reaction is given as, rate=4.7x10^(-5), [RX][OH(-)]+0.24xA0^(-5)[RX],what percentage of RX reacts by SN2 mechanism when [OH(-)]=0.001 molar

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!