Help finding zeros? Medal awarded :)

Question

anonymous · Answer

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anonymous · Answer

set each factor equal to zero and solve
$x+2=0$ gives $x=-2$ 
$x+5=0$ means $x=-5$ and 
$x=0$ means... well it means $x=0$
so you have 3 zeros, namely $0,-2,-5$

anonymous · Answer

first person who explains or just give me answer gets medal D:

anonymous · Answer

OMG! thank you i remember doing this last year and now i remember holy crap thank u :D

anonymous · Answer

yw, not too bad, was it?

anonymous · Answer

can you help me out with one more? & no not at all i just totally forgot what it meant lol

anonymous · Answer

sure

anonymous · Answer

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anonymous · Answer

$$f(x)=x^4-4x^3+3x^2$$ factor out the common factor of $x^2$ first and get 
$$f(x)=x^2(x^2-4x+3)$$ 
now factor the second part to get 
$$f(x)=x^2(x-3)(x-1)$$ and now the zeros are easy to find

anonymous · Answer

just like before 
$x-3=0$ means $x=3$
$x-1)=0$ gives $x=1$ and $x^2=0$ gives... $x=0$

anonymous · Answer

YEAH! okay i get it now so 3,1,0 :D

anonymous · Answer

is that the second answer ??

anonymous · Answer

three zeros, they are $0,1,3$ and because the $x^2=0$ has an exponent of 2, the "multiplicity" of that zero is 2

anonymous · Answer

yes, go with answer B

anonymous · Answer

awesome thank you so much you're a life saver <3

anonymous · Answer

yw
hope you are done