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Mathematics 12 Online
OpenStudy (anonymous):

A sample of 250 grams of radioactive substance decays at a rate of 34% per year. Write the equation for radioactive decay of this substance.

OpenStudy (anonymous):

Here are my answer choices: 250(1.34)^t 250e^.34t 250(0.66)^t 250e^-.34t

OpenStudy (anonymous):

If it decays at 34% per year what percent is left after a year?

OpenStudy (anonymous):

We thought it would be C, but someone got it wrong when they did that. I don't know if it could be d possibly?

OpenStudy (anonymous):

It is C. No if's, and's, or but's about that. A = starting amount = 250 grams so you have 250(1 - .34)^t 0r 250(.66)^t

OpenStudy (anonymous):

If someone wrote C and got it wrong, let that person go back and ask for credit.

OpenStudy (anonymous):

Assuming that C is 250(.66)^t.

OpenStudy (anonymous):

@bkeith2698

OpenStudy (anonymous):

We learned the other day that it's also possible to put this in the form \[P=P_{0}e ^{kt}\] where p is the current value. p0 is the initial, e is the base of a natural log, k is the percent decrease/increase and t is the time. Would that make d right? I think it would.

OpenStudy (anonymous):

@Easyaspi314

OpenStudy (anonymous):

the 34 percent of 250 is107 so 250 are the initial grams and t is the time in years so.. EQUATION=250-107t And that´s it

OpenStudy (anonymous):

Can't be. not an answer choice. thanks for the help though @julian9922

OpenStudy (anonymous):

click on best response please

OpenStudy (anonymous):

Two people have helped me, I will give the best response to the one that solves CORRECTLY. @julian9922 and @Easyaspi314

OpenStudy (anonymous):

i helped you the most and it was easy to understand my explanation

OpenStudy (anonymous):

You told me what I already knew......not why I came on here......@julian9922

OpenStudy (anonymous):

so wht do you need?i will help you also

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