Question

Find the maximum or minimum of the following quadratic function: y = -3x^2 + 14x + 8

Answer 1

The vertex of a parabola can be found from this equation y=ax^2+bx+c pretty easily by using the formula for the vertex (-b/(2a), f(-b/(2a))
If a<0, then the parabola is open downwards and has a max.
If a>0, then the parabola is open upwards and has a min.

Answer 2

Okay but I still dont understand how to solve it

Answer 3

y=ax^2+bx+c
y=-3x^2+14x+8
what is a,b,c?

Answer 4

I figured out the answer its (14/6,101/3) and 101/3 is the maxium

Answer 5

ok the x-coordinate is right...
and the y-coordinate is...

Answer 6

I got something different for the y-coordinate.

Answer 7

-3(14/6)^2 + 14(14/6) + 8

Answer 8

Oh what was it

Answer 9

73/3

Answer 10

I gave you a medal for the finding where the max occurred
and the actual max is f(-b/2a) which is 73/3
Good job

Answer 11

Thanks. Goodbye