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Mathematics 8 Online
OpenStudy (anonymous):

Some steps to rewrite the expression x3 - 16x + x2 - 16 as a product of three factors are shown below: Step 1: x3 - 16x + x2 - 16 Step 2: x3 + x2 - 16x - 16 Step 3: x2(x + 1) - 16(x + 1) Which of the following best shows the next two steps to rewrite the expression? a. Step 4: (x2 + 16)(x + 1); Step 5: (x + 4)(x + 4)(x + 1) b. Step 4: (x2 - 16)(x + 1); Step 5: (x + 4)(x + 4)(x + 1) c. Step 4: (x2 - 16)(x + 1); Step 5: (x - 4)(x + 4)(x + 1) d. Step 4: (x2 + 16)(x + 1); Step 5: (x - 4)(x + 4)(x + 1)

OpenStudy (jdoe0001):

so.... what do you think?

OpenStudy (jdoe0001):

how about taking common factor? \(\bf x^2\color{blue}{(x + 1)} - 16\color{blue}{(x + 1)}\) do you see any we can use?

OpenStudy (anonymous):

I couldnt decide between B and C @jdoe0001

OpenStudy (jdoe0001):

well. what would be YOUR next step ?

OpenStudy (anonymous):

I know how to do step 4, but i forgot how to do step 5 ): @jdoe0001

OpenStudy (jdoe0001):

ok.... well, let's take one STEP at a time =)... what would be step 4?

OpenStudy (anonymous):

the answer for step 4 is (6^2-16)(x+1)

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

@jdoe0001

OpenStudy (jdoe0001):

ohh yes, that'd be step number 4, sorry I got a bit caught up

OpenStudy (anonymous):

its okay (: what do i do next?

OpenStudy (jdoe0001):

\(\bf x^2(x+1)-16(x+1)\implies (x^2-16)(x+1)\\ \quad \\ \textit{recall that }\qquad a^2-b^2 = (a-b)(a+b)\qquad thus\\ \quad \\ (x^2-16)(x+1)\implies (x^2-4^2)(x+1)\implies (x-4)(x+4)(x+1)\)

OpenStudy (anonymous):

THANK YOU THANK YOU THANK YOU!!!

OpenStudy (jdoe0001):

yw

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