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Mathematics 14 Online
OpenStudy (coledrf):

2(3x+5)=46 solve

OpenStudy (mathlegend):

Do you know how to distribute @coledrf?

OpenStudy (coledrf):

a.4 b.5 c.6 d.7

OpenStudy (coledrf):

yes

OpenStudy (mathlegend):

Do that for me and tell me what you get.

OpenStudy (coledrf):

2(5x+10)=46

OpenStudy (coledrf):

i think

OpenStudy (mathlegend):

You start here: 2(3x+5)=46 Which means you need to multiply the 3 and 5 inside the parenthesis by the 2... so do that and tell me what you get.

OpenStudy (coledrf):

2(6x+10)=46

OpenStudy (mathlegend):

Good except the 2 on the outside is gone.

OpenStudy (coledrf):

ok

OpenStudy (mathlegend):

6x + 10 = 46

OpenStudy (coledrf):

x=6

OpenStudy (coledrf):

!!!

OpenStudy (mathlegend):

Yes.

OpenStudy (coledrf):

wooh

OpenStudy (mathlegend):

See you know how to do this!

OpenStudy (coledrf):

ok let me try another one

OpenStudy (coledrf):

1/2x+1/4x=16

OpenStudy (mathlegend):

Do you know how to add fractions?

OpenStudy (coledrf):

i am really bad with fractions they scare me

OpenStudy (coledrf):

:/

OpenStudy (mathlegend):

When dealing with adding or subtracting fractions... you are concerned with getting the denominators to be the same... so the numbers at the bottom must be identical. We do this by multiplying one or both of the fractions to get the same denominator.

OpenStudy (mathlegend):

1/2 + 1/4 What can we multiply the 1st fraction by to get a 4?

OpenStudy (coledrf):

yes lcd right? d\so it would be 2/4x+1/4x=16

OpenStudy (mathlegend):

Least common multiple... and yes you are correct!

OpenStudy (mathlegend):

So add them up and what do you get?

OpenStudy (coledrf):

3/8? or 3/4

OpenStudy (mathlegend):

Denominator does not change when adding... so 3/4

OpenStudy (coledrf):

ok

OpenStudy (mathlegend):

3/4x = 16 To get rid of the denominator we multiply both sides by it... so it looks like:

OpenStudy (mathlegend):

\[4(\frac{ 3 }{ 4 })=16(4)\]

OpenStudy (coledrf):

ok

OpenStudy (mathlegend):

So clean that up for me.

OpenStudy (coledrf):

then devide by 3?

OpenStudy (mathlegend):

Show me what you got first.

OpenStudy (coledrf):

3= 64?

OpenStudy (coledrf):

then devide by 3?

OpenStudy (mathlegend):

Right 3x=64 Then, yes you divide by 3.

OpenStudy (coledrf):

and x=21.3333333333333 lol

OpenStudy (mathlegend):

Yup

OpenStudy (coledrf):

yay

OpenStudy (coledrf):

will you stay with me ily

OpenStudy (coledrf):

6-x-x=18

OpenStudy (mathlegend):

So for the x's .. isn't it true that you can place a 1 in front? to look like... 6 - 1x- 1x= 18

OpenStudy (coledrf):

ok

OpenStudy (mathlegend):

So combine your x's (Like Terms)

OpenStudy (coledrf):

so 6-2x=18

OpenStudy (mathlegend):

Yes, now solve it like you would a regular equation.

OpenStudy (coledrf):

im confused

OpenStudy (coledrf):

oh wait never mind

OpenStudy (mathlegend):

Lets rewrite then... -2x+6=18

OpenStudy (coledrf):

yea thats what was confusing me i got this

OpenStudy (coledrf):

-6?

OpenStudy (mathlegend):

Yes, so you have got this. You understand equations pretty well.

OpenStudy (coledrf):

yes theres just one more can u help me with ?

OpenStudy (coledrf):

4x-3/5=2/5

OpenStudy (coledrf):

hello @MathLegend

OpenStudy (mathlegend):

How can we move 3/5 to the other side?

OpenStudy (coledrf):

i think the answer is 1/4?

OpenStudy (mathlegend):

Okay, let me check I didn't do the equation.

OpenStudy (coledrf):

ok

OpenStudy (mathlegend):

You are correct!

OpenStudy (coledrf):

woo i couldnt have done it with out you

OpenStudy (coledrf):

thank you so much

OpenStudy (mathlegend):

You are welcome

OpenStudy (coledrf):

closing the quetion

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