Alan is building a garden shaped like a rectangle with a semicircle attached to one short side. If he has 20 feet of fencing to go around it, what dimensions will give him the maximum area in the garden?
You need to find the rectangle area and semicircle area. Then add them together.
Here is how to find the maximum area of a rectangle with a fixed perimeter. In short it turns out to be a square. so the relationship you need to solve is the semicircle length to the other three equal sides. Perimeter = 2(L + W) 100 = 2(L+W) L+W = 50 --- Let width be W Then length = 50-W -------- Area = length * width A = (50-W)W A = 50W-W^2 -- This is a quadratic with a = -1, b = 50: Maximum area occurs when W = -b/2a = -50/-2 = 25 Since W = 25 and L+W=50, L = 25
@ehuman are you sure thats right if you demonstrate it in a drawing i will tick you as best response
|dw:1383964113672:dw|
Join our real-time social learning platform and learn together with your friends!