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Mathematics 13 Online
OpenStudy (anonymous):

Alan is building a garden shaped like a rectangle with a semicircle attached to one short side. If he has 20 feet of fencing to go around it, what dimensions will give him the maximum area in the garden?

OpenStudy (ashley_f97):

You need to find the rectangle area and semicircle area. Then add them together.

OpenStudy (anonymous):

Here is how to find the maximum area of a rectangle with a fixed perimeter. In short it turns out to be a square. so the relationship you need to solve is the semicircle length to the other three equal sides. Perimeter = 2(L + W) 100 = 2(L+W) L+W = 50 --- Let width be W Then length = 50-W -------- Area = length * width A = (50-W)W A = 50W-W^2 -- This is a quadratic with a = -1, b = 50: Maximum area occurs when W = -b/2a = -50/-2 = 25 Since W = 25 and L+W=50, L = 25

OpenStudy (anonymous):

@ehuman are you sure thats right if you demonstrate it in a drawing i will tick you as best response

OpenStudy (anonymous):

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