HELP ME PLEASE :( In △JKL, KM is an altitude. What is the length, in units, of JK?
JM/KM = KM/ML Right?
I have no idea D:
Okay, there are similar triangles created any time you drop an altitude in a right triangle. So the three triangles are all proportionate to each other. I mean the ratios of their corresponding sides will equal.
So JM is a longer leg of the medium sized triangle and KM is the longer leg of the smallest triangle. Both of these lengths divided by the shortest side of the same triangle will be the same number. For the medium sized triangle, JKM, the shortest side is KM. For the smallest triangle, KML, it is ML. So JM/KM = KM/ML
I know that there are 2 similar but I dont know how to get the sides length. Here are my options: 7 radical 5 5 radical 7 12 7
I hate denominators, so I multiply both sides by the denominators to get: JM*ML = KM^2
If jm=5 and jl is 35, is ml=30???
You sure one of the options isn't 5 radical 6?
positive
could the 35 actually be for ML?
Thats what I thought it was becauseX^2+= 150 and thats 5 radical 6.. And yeah. I posted a picture of the triangle..
Nevermind, I thought it was looking for KM. The answer is there, no worries.
But how would I solve it? Im confused. They didnt show how to solve this kind of problem
you now have 5 and 5 radical 6 for two legs of a right triangle. You know how to find the hypotenuse...
not a clue :(
a^2 + b^2 = c^2
oh. yeah. but how would I use that in this problem?
5^2 + (5√6)^2 = 175 then √175
so 5 squareroot 7?
yes
Yay! Can you check my other answers?
for a little while, but start a new thread, this one is pretty long.
okay. In △PQR, QS is an altitude. Solve for x and y.
i said x=6 and y= 3 squareroot 13
Yes. I get the same
okay and one more then Im good :) In △ABC, BD is an altitude. What is the length, in units, of BD? I said 5 squareroot 6
yes
OKay Thank you so much for your time :)
Bye!
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