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Prove that if [z^2 / (z-1) ] is real, then the point represented by the complex number z lies either on the real axis or on a circle passing through the origin.
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let z = x+iy so, we know that \(\large \dfrac{x^2+y^2}{(x-1)+iy}\) is REAL. So, Equate the IMAGINARY PART of this = 0 when you multiply and divide by the conjugate of denominator, the imaginary part has the numerator of \(\large y(x^2+y^2)\) which when we equate to 0 , we get the required result :)
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