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Is this a one to one function? http://tinypic.com/r/v5bdbp/5
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enopw
ignore my answer. i made a mistake
Well do you know the answer?
no
i think it is
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Well thats not very helpful @Euler271
No, it is not. A function is injective ('one-to-one') iff it does not map more than one value to its range from each value of its domain.
This is clearly not injective, since: \[ \lfloor.2\rfloor=\lfloor.4\rfloor \]Which is a counter example.
Thanks @LolWolf
But is it a function?
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It is a function, but it is not one-to-one.
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