Does the series converge or diverge? sqrt(n^4+1)/5n^2 This one i actually need help on...what test do I use for this one? @LolWolf
Try using a direct comparison. Here: \[ \frac{\sqrt{n^4+1}}{5n^2}=\frac{1}{5}\sqrt{\frac{n^4}{n^4}+\frac{1}{n^4}}>\;? \]
p>1 converges
i dont see how you got the fractions under the sqrt though
jk i see it now
sorry its been a long night!
No, it doesn't quite converge. Note that:\[ \sqrt{\frac{n^4}{n^4}+\frac{1}{n^4}}=\sqrt{1+\frac{1}{n^4}}>1 \] And, clearly: \[ 1+1+1+1+1+1+\cdots=\infty \]
but since its larger than 1, because of the p-series it converges? I'm sorry im not quite seeing it
Remember that the p-series refers to the exponent of the inverse: \[ \sum_n\frac{1}{n^p} \]This is not an exponent, this is the actual number: \[ \sum_n\sqrt{1+\frac{1}{n^4}}>\sum_n 1=\infty \]Sum 1 infinitely many times and you should have infinity.
oooh okay! i get it now...thank you:)
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