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Mathematics 40 Online
OpenStudy (anonymous):

Determine the point(s) at which the graph of the function has a horizontal tangent line. MEDAL WILL BE REWARDED!!! f(x)=x^2/(x^2+1)

hartnn (hartnn):

horizontal lines have 0 slope , right ? so, just differentiate f(x) and equate f'(x) = 0

OpenStudy (anonymous):

So my horizontal line is 0,0?

hartnn (hartnn):

f'(c) gives the slope of tangent at point c but the tangent we need is horizontal so, its slope = 0 thats why we put f'(x) = 0

OpenStudy (anonymous):

yes so my final answer is f'(x) is 0,0?

hartnn (hartnn):

ohh, let me calculate ...

OpenStudy (anonymous):

I think its either 0,1 or 0,0

hartnn (hartnn):

i get x = 0 too so, f(0) = 0 and yes, so the point is (x,f(x)) = (0,0) is correct :)

OpenStudy (anonymous):

awesome thank you :) More questions to come!

hartnn (hartnn):

welcome ^_^

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