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Find the given higher-order derivative. MEDAL WILL BE REWARDED! f''(x)=2-(2/x), f'''(x)
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just differentiate 2-2/x once
So wait...let me calculate this...
Im confused on what to do
yeah, \(\dfrac{d}{dx}f''(x)=f'''(x)\)
\(\large f'''(x)=\dfrac{d}{dx}(2-\dfrac{2}{x})\)
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so would it be 2^2-x^2?
2^2 ?
whats d/dx 2 = .. ?
derivative of a constant is = ... ?
it equals -2/dx^3
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no... derivative of a constant is 0
So we have 0-2/x?
derivative of (1/x) will be ... ?
-1/x^2
yes, so d/dx (-2/x) will be 2/x^2 right ?
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yes
thats your f'''(x)
ohhhhh okay, I see how you go that! Thank you
welcome ^_^
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