Use the given information to find f'(2). MEDAL WILL BE REWARDED! g(2)=3 g'(2)=-2 h(2)=-1 h'(2)=4 f(x)=g(x)h(x)
@hartnn
use product rule
How do I incorporate these into this equation? Am I changing the equation first?
f'(x) = ... ? then you just put x =2
okay so hold on give me one sec...
f(2)=3(2)-1(2)??
why 2 ? \(\large f'= g'h +h'g \) right ?
it was x so I thought I was subsitituing f(2)?
\(\large f'(x)= g'(x)h(x) +h'(x)g(x)\) \(\large f'(2)= g'(2)h(2) +h'(2)g(2)\) makes sense ?
oh okay, so I plug in h and g now?
yes, all values are given...
okay let me calculate
okay so before I go any further I have f'(2)=(-2)(2)(-1)(2)+(4)(2)(3)(2)
what ? \(\large f'(2)= g'(2)h(2) +h'(2)g(2) \\ \large f'(2)=-2 (-1)+4(3)\)
oh okay....so my final answer would be f'(2)=2+12 so f'(2)=14?
yes.
Awesome! thank you, this one really was confusing!
Join our real-time social learning platform and learn together with your friends!