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OpenStudy (anonymous):
Use the given information to find f'(2). MEDAL WILL BE REWARDED!
g(2)=3 g'(2)=-2
h(2)=-1 h'(2)=4
f(x)=g(x)h(x)
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OpenStudy (anonymous):
@hartnn
hartnn (hartnn):
use product rule
OpenStudy (anonymous):
How do I incorporate these into this equation? Am I changing the equation first?
hartnn (hartnn):
f'(x) = ... ?
then you just put x =2
OpenStudy (anonymous):
okay so hold on give me one sec...
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OpenStudy (anonymous):
f(2)=3(2)-1(2)??
hartnn (hartnn):
why 2 ?
\(\large f'= g'h +h'g \)
right ?
OpenStudy (anonymous):
it was x so I thought I was subsitituing f(2)?
hartnn (hartnn):
\(\large f'(x)= g'(x)h(x) +h'(x)g(x)\)
\(\large f'(2)= g'(2)h(2) +h'(2)g(2)\)
makes sense ?
OpenStudy (anonymous):
oh okay, so I plug in h and g now?
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hartnn (hartnn):
yes, all values are given...
OpenStudy (anonymous):
okay let me calculate
OpenStudy (anonymous):
okay so before I go any further I have f'(2)=(-2)(2)(-1)(2)+(4)(2)(3)(2)
hartnn (hartnn):
what ?
\(\large f'(2)= g'(2)h(2) +h'(2)g(2) \\ \large f'(2)=-2 (-1)+4(3)\)
OpenStudy (anonymous):
oh okay....so my final answer would be f'(2)=2+12 so f'(2)=14?
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hartnn (hartnn):
yes.
OpenStudy (anonymous):
Awesome! thank you, this one really was confusing!
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