MATH GENIUS NEEDED!!
So in calculus i learning about Derivatives and i need help with Diffrientiability.
Question 1: If possible, give an example of where a function is differentiable at a point but not continuous at that point.
not possible. if a function is differentiable at a point it is also continuous at the point
please write a question
Indeed what he said, for a function to be differentiable at a point it must also be continuous at that point.
ty! Without a graph, how can one show differentiability of a function at a point?
By differentiating the function, and plugging in that point and checking it's valid.
GJ agent
Where is the function \[g(x) = 3x ^{2} - x +5\] differentiable?
so it is differentiable everywhere no problems with any point and no points of discontinuities
okay.
Explain why the definition of a numerical derivative does not exist at x = 2 in the graph shown.
well we can think of it as a slope. you see that that slope right before x = 2 is infinity and right after is -infinity so the slope of the graph at this point is not defined
oh. its an asymptote?
no, asymptote is different. in our case its the slope value that goes to infinity and not the values of the function that goes to inf!
oh. Okay.
Explain why the definition of a numerical derivative does not exist at x = 2 in the graph shown.
so the derivative at both sides of the point should be the same we can see that if we come to the point from left the derivative is negative whereas when we come from the right it is positive
If a graph has ANY kind of corner like that, it is not differentiable at that point. Smooth curves are differentiable. Corners are not. If the slope suddenly changes, as it does in a corner = not differentiable
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