A hydraulic press for compacting powdered samples has a large cylinder which is 10.0 cm in diameter, and a small cylinder with a diameter of 2.0 cm. A lever is attached to the small cylinder as shown in (Figure 1) . The sample, which is placed on the large cylinder, has an area of 4.0 cm2.

What is the pressure on the sample if F = 350N is applied to the lever?

Question

A hydraulic press for compacting powdered samples has a large cylinder which is 10.0 cm in diameter, and a small cylinder with a diameter of 2.0 cm. A lever is attached to the small cylinder as shown in (Figure 1) . The sample, which is placed on the large cylinder, has an area of 4.0 cm2.

What is the pressure on the sample if F = 350N is applied to the lever?

anonymous · Answer

@Loser66

anonymous · Answer

http://session.masteringphysics.com/problemAsset/1697143/5/Giancoli7.ch10.p21_1.jpg

loser66 · Answer

@Vincent-Lyon.Fr

anonymous · Answer

first found the Pressure of small cylinder P=F/A 

P = 700N/ 3.14x10^-4 = 2229299.363

then found force for hydraulic fluid 

F = (2229299.363) (0.0079m2) = 17611.46N

then find then pressure of sample 

P = 17611.46 / 0.04 = 440286.6242 Pa

anonymous · Answer

this is is wrong, i dont seee why it would be wrong?

vincent-lyon.fr · Answer

4 cm² is not 0.04 m²

anonymous · Answer

ohh right! i totally forgot, it would be 4x 10^-4

vincent-lyon.fr · Answer

yep!

anonymous · Answer

yessss finally got it...thank you soo much!

vincent-lyon.fr · Answer

440286.6242  has an excessive number of significant figures.

Besides, the right answer is 4.375 10^7 Pa

Forget about $\pi$ in your calculation. Left cylinder has just a surface area 25 times as large as that of right cylinder.

anonymous · Answer

yes i got that answer, thank you very much =D  me and my silly mistakes lol