Question

I need help on this question!

A ball is thrown into the air with an upward velocity of 32 feet per second. It’s height, h, in feet after t seconds is given by the function h(t) = - 16t^2 + 32t + 6. What is the ball’s maximum height? How long does it take the ball to reach its maximum height? Round to the nearest hundredth, if necessary

a. Reaches a maximum height of 22 feet after 1.00 second.
b. Reaches a maximum height of 22 feet after 2.00 seconds.
c. Reaches a maximum height of 44 feet after 2.17 seconds.
d. Reaches a maximum height of 11 feet after 2.17 seconds.

Answer 1

Do you know how to get vertex form?

Answer 2

no

Answer 3

This question is easier if you answer the second question first, then the height question.

Do you know how to take the derivative of a function and what that means?

Answer 4

I do not! :/

Answer 5

look at the attachment. x=-b/2a is where your equation is gonna have a max or min. in this case x=-b/2a will give you the time that it took for it to reach the max. when you plug in the x value you'll find the maximum height.