Question

What is the equation of the line that passes through the point (6, 1) and is perpendicular to the line y = -3x + 2? Please Help!

Answer 1

what is the slope of the given line?

Answer 2

For y=-3x+t, the slope is m=-3

Answer 3

good

Answer 4

that's the same as -3/1

Answer 5

now flip the fraction to get -1/3

then flip the sign to get +1/3 or just 1/3

Answer 6

so the slope of ANY perpendicular line to this given line is 1/3

Answer 7

so you now know the slope of this line, which is 1/3

and you also know that this line goes through (6,1)

Answer 8

let me know if that's enough to get started

Answer 9

Ok so, here are my answer choices just to help:
y = -3x + 3
y = -3x - 9
y = 1/3 x - 1
y = 1/3 x + 19

Answer 10

use y = mx + b

Answer 11

m = 1/3
x = 6
y = 1

Answer 12

y = mx + b

y = (1/3)x + b ... plug in m = 1/3

1 = (1/3)(6) + b ... plug in x = 6, y = 1

now solve for b

Answer 13

So it would be answer choice D?

Answer 14

y = 1/3 x + 19

Answer 15

Wait, I think

Answer 16

(1/3)*6 = (1/3)*(6/1) = (1*6)/(3*1) = 6/3 = 2

so,

(1/3)*6 = 2

Answer 17

that might help

Answer 18

oh, C

Answer 19

?

Answer 20

what did you get when you solved for b

Answer 21

3

Answer 22

that's not correct

Answer 23

1 = (1/3)(6) + b

1 = 2 + b

b = ???

Answer 24

I suck at this I'm sorry

Answer 25

2+b is the same as b+2

Answer 26

1 = 2 + b

1 = b + 2

b + 2 = 1

b = ???

Answer 27

keep practicing and you'll get better at it

Answer 28

-1?

Answer 29

good

Answer 30

m = 1/3
b = -1

Answer 31

therefore

y = mx + b

turns into

\[\large y = \frac{1}{3}x - 1\]

Answer 32

Wohoo! Thanks so much!

Answer 33

you're welcome