Maximizing the volume of a cone with radius 12cm and determine the angle (A) needed to create this.
A cone, as drawn above, has a volume given by \[V=\frac{ 1 }{ 3 }*\pi*r ^{2}*h\] Since \[\cot \left( \Theta \right)=\frac{ h }{ r }\] we can rewrite the formula in the following steps: \[V=\frac{ 1 }{ 3 }*\pi*r ^{2}*h*\frac{ r }{ r }\] \[V=\frac{ 1 }{ 3 }*\pi*r ^{3}*\frac{ h }{ r }\] \[V=\frac{ 1 }{ 3 }*\pi*r^3*\cot \left( \Theta \right)\] Using this formula (and considering r as a constant 12cm): as theta gores toward zero (from some positive value), V gets larger and larger toward infinity (which would correspond to height going toward infinity. However, since theta can never actually have a value of zero due to physical impossibility, there is no maximum value for the volume.
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Ah, you beat me to it manetbo! My browser refreshed and I lost my picture and everything haha! I will second your answer! Nice write up!!
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