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Suppose you rotate triangle ABC counterclockwise 90º. If ABC has vertices A (-2, 1), B (-1, 4), and C (2, 2), vertex A' is (-1, ?).
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I assume you mean rotating the triangle about the origin. If so, the rule to do that is (-y, x).
How do you apply that rule?
So the original coordinates of A are (-2, 1) which is in the form (x, y). -2 is the x and 1 is the y. Now plug those into (-y, x)
That would give me (2, 1), but the question itself says that the X point of the rotated vertices is -1?
Actually it would give you (-1, -2) because 1 is the y value and it needs to be negated and then put before the x value, -2.
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Oh shoot! I see where I went wrong with your instructions, thank you I understand!
Okay :) glad I could help
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