Mathematics
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OpenStudy (anonymous):
is x + 10 a factor of the function f (x) = x^3 - 75x + 250?
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OpenStudy (anonymous):
try algebraic long division. If you dont get a remainder then it is factor :)
OpenStudy (anonymous):
hmm can you explain further?
OpenStudy (anonymous):
try that. ANd i will add if you get no remainder left then it is a factor
OpenStudy (anonymous):
i still dont get it at all
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OpenStudy (anonymous):
can you do a walkthrough with my example?
jimthompson5910 (jim_thompson5910):
hint: if x-p is a factor of f(x), then f(p) = 0
this is the remainder theorem
OpenStudy (anonymous):
can someone do a step by step walkthrough of my problem please
jimthompson5910 (jim_thompson5910):
x + 10
is the same as
x - (-10)
jimthompson5910 (jim_thompson5910):
match x - (-10) up with x - p and you'll see that p = -10
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jimthompson5910 (jim_thompson5910):
so you just need to see if f(-10) = 0 is true or not
OpenStudy (anonymous):
not true
OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
you need to show why it's not true
jimthompson5910 (jim_thompson5910):
plug x = -10 into f (x) = x^3 - 75x + 250 to see what you get
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OpenStudy (anonymous):
-10 cubed is -1000 correct?
jimthompson5910 (jim_thompson5910):
yes it is
OpenStudy (anonymous):
ok then the function would equal
OpenStudy (anonymous):
-1500?
OpenStudy (anonymous):
is that right?
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jimthompson5910 (jim_thompson5910):
you made an error
jimthompson5910 (jim_thompson5910):
try it again
OpenStudy (anonymous):
-1000+750+250= 0 so 0 is the answer
jimthompson5910 (jim_thompson5910):
so because f(-10) = 0, this means that x - (-10) or x + 10 is a factor
OpenStudy (anonymous):
so it is a factor because the remainder is zero?
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OpenStudy (anonymous):
or is it a factor because the remainder is NOT zero?
jimthompson5910 (jim_thompson5910):
it's a factor because the remainder is 0
jimthompson5910 (jim_thompson5910):
that's exactly what the factor theorem says above
OpenStudy (anonymous):
thank you so much man!
OpenStudy (anonymous):
hey can you help me with a couple more?
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OpenStudy (anonymous):
they deal with remainder questions in long division
jimthompson5910 (jim_thompson5910):
sure, one more