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OpenStudy (anonymous):
Find the integral using substitution:
(2+ ln x)^1/2/(x)
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OpenStudy (anonymous):
let u = (2+ln x)
ganeshie8 (ganeshie8):
\(\large \frac{(2+ ln x)^{\frac{1}{2}}}{x}\)
ganeshie8 (ganeshie8):
like that ?
OpenStudy (anonymous):
What is du?
OpenStudy (anonymous):
Yes, ganeshie8, just like that.
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OpenStudy (anonymous):
du= 1/x?
ganeshie8 (ganeshie8):
since we can deal wid ENTIRE thing inside radical at a time,
simply sub whatever inside radical as u
OpenStudy (anonymous):
yes...so what form does the integral have?
OpenStudy (anonymous):
"dx" if that is what you are looking for.
OpenStudy (anonymous):
If u = (2+lnx), then du = dx/x...agree?
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OpenStudy (anonymous):
dx/x = (1/x) dx
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
So the entire integrand called (2 + ln x)^(1/2) dx/x transforms into the form u^(1/2) du....agree?
OpenStudy (anonymous):
because u = 2+ln x and everything else is just du, so you have u^1/2 du
OpenStudy (anonymous):
Yes i got to that step and then I got confused and did not know what to do.
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OpenStudy (anonymous):
the integral of u^(1/2) du is just u^(3/2)/(2/3) = 2/3 (u^(3/2) + C
Now just substitute (2+ln x) for u
OpenStudy (anonymous):
Oh, I think I over complicated it when I was trying to work through it. Thank you Easyaspi314.
OpenStudy (anonymous):
welcome.
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