Question

A 4.4 kg object is being pushed along a surface,
causing it to accelerate at a rate of 1.5 m/s2
. Th e
coeffi cient of kinetic friction is 0.25. What is the
magnitude of the horizontal force being applied to
push the object?

Answer 1

Sum of the forces = mass * acceleration there for Fnet = 4.4*1.5 = 6.6 N

The two forces that are acting on the object are friction (Ff) and the applied force (Fa)

Ff = mu*Normal force = mu*m*g = 0.25*4.4*9.8 = 10.78 N

Also Fnet = Fa - Ff

So Fa = Fnet + Ff = 10.78 +6.6 = 17.38 N

I hope that helps

Answer 2

therefore*

Answer 3

Thank you so much @melaghil !