Mathematics
6 Online
OpenStudy (anonymous):
Simplify the complex algebraic expression:
(12x^3)/(7y^4)/(3x^5)/(2y)
12 years ago
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OpenStudy (mathlegend):
Are they two fractions?
12 years ago
OpenStudy (anonymous):
Yes.
12 years ago
OpenStudy (mathlegend):
So upon having division of fractions... we never really divide. We multiply instead. So in order to do this... we need to flip the 2nd fraction. (Reciprocal)
12 years ago
OpenStudy (mathlegend):
\[\frac{ 12x ^{3} }{ 7y ^{4} }*\frac{ 2y }{ 3x ^{5} }\]
12 years ago
OpenStudy (mathlegend):
So multiply straight across please and tell me what you get.
12 years ago
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OpenStudy (anonymous):
(24x^3y)/(21x^5y4)?
12 years ago
OpenStudy (mathlegend):
Yes!
12 years ago
OpenStudy (mathlegend):
Now, can't we simplify? Lets start with the whole numbers out front...
12 years ago
OpenStudy (mathlegend):
\[\frac{ 24 }{ 21 }\]
12 years ago
OpenStudy (mathlegend):
What does that reduce to?
12 years ago
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OpenStudy (anonymous):
8/7..
12 years ago
OpenStudy (mathlegend):
Good... so now we have...
12 years ago
OpenStudy (mathlegend):
\[\frac{ x ^{3}y }{ x ^{5}y ^{4} }\]
12 years ago
OpenStudy (mathlegend):
Now, lets do the x's first... we know that 5-3 = 2 right?
12 years ago
OpenStudy (anonymous):
(8/7x^3y^3
12 years ago
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OpenStudy (mathlegend):
Since the 5 is the bigger number it determines where the x^2 will end up... 5 is on the bottom so that is where the x^2 will go
12 years ago
OpenStudy (mathlegend):
Wow, @Katelynmorris you are good, just minor error... it should be x^3
12 years ago
OpenStudy (mathlegend):
x^2
12 years ago
OpenStudy (mathlegend):
sorry!
12 years ago
OpenStudy (anonymous):
Thank you! :)
12 years ago