Question

(1+1/x)/(1-1/x^2)

Answer 1

\[\frac{ 1+\frac{ 1 }{ x } }{ 1-\frac{ 1 }{ x^2 } }\]
Correct?

Answer 2

rewrite the numerator and denominator with common denominators


1 + 1/x = (x +1)/x

1 - 1/x^2 = (x^2 -1)/x^2

so you are dividing by a fraction, flip and multiply

\[\frac{(x +1)}{x} \times \frac{x^2}{(x^2 -1)}\]

cancel common factors...

and the term x^2 -1 can be factorised... and you may see another common factor

hope this helps

Answer 3

Yes @donny471

Answer 4

Ok, let me know if his explanation is enough.

Answer 5

Could you help me with another problem? (1/x)-(1/y)/(y/x^2)-(1/y)

Answer 6

well again... writing the numerator and denominators of the problem as fractions with common denominators is the key...