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Mathematics 13 Online
OpenStudy (anonymous):

Do you agree or disagree with the statement “the instantaneous rate of change of the function f(x) = ln(x) / x5 at the point (1,0) is 1” ? Show working to support answer.

OpenStudy (anonymous):

Find the derivative via quotient rule. Then evaluate the derivative at x = 1. Do you get 1? Work it out and you'll see that it is 1.

OpenStudy (anonymous):

derivative of ln x = 1/x derivative of x^5 is 5x^4

OpenStudy (anonymous):

so how you get 1 from that

OpenStudy (anonymous):

what is the derivative of the function (using the Quotient Rule)?

OpenStudy (anonymous):

[(x^5)(1/x) - (ln x)(5x^4)]/x^10 Evaluate at x = 1, you should get 1 (since ln 1 = 0).

OpenStudy (anonymous):

how you get X^10

OpenStudy (anonymous):

The quotient rule says, that the denominator is (x^5) squared, which is x^10

OpenStudy (anonymous):

ok thanks ..... so where do the coordinates (1,0) come in?

OpenStudy (anonymous):

we are interested in the x-coordinate x = 1. The instantaneous rate of change is simply the derivative at x = 1.

OpenStudy (anonymous):

oh I replaced x which is equal to 1 into quotient rule and I got 1

OpenStudy (anonymous):

exactly, so the statement is true.

OpenStudy (anonymous):

Thanks very much

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