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Mathematics 16 Online
OpenStudy (moongazer):

How to find the anti-derivative of this?

OpenStudy (moongazer):

\[\int\limits (5t+2)^4 dt\] my teacher said you can't directly use the formula: [u^(n+1)]/[n+1] + c but in the problem \[\int\limits (x-2)^2 dx\] she just let me use the formula isn't it that its just the same?

OpenStudy (anonymous):

No. The derivative of (x-2) is just 1. The derivative of (5t+2) is 5. so you have to account for that 5. So you would need to pull out 1/5 in front of the integral to account for that 5. So when integrating (x-2)^4 dx, then you can use the rule of u^n...as u = x -2, du = dx. But in the integral of (5t+2), if u = 5t + 2, du = 5 dt...and dt = 1/5 du, and that is where you are "pulling out" the 1/5.

OpenStudy (anonymous):

So...in essence, if u = any function of x, and du = dx, then you can use the rule for integrating u^n as u^(n+1)/(n+1).

OpenStudy (moongazer):

I think I already got the idea but still didn't fully understand the concept. how about if it is something like \[\int\limits (x^3+2)^4 dx\]

OpenStudy (anonymous):

If u = (x^3 + 2), then du = 3x^2 dx....so you are stuck.

OpenStudy (anonymous):

so you cannot use the rule of integral u^n.

OpenStudy (moongazer):

so you can use the u^n integral rule only for the integrand in the form something like (kx +c)^n ?

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