Question

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Answer 1

do tell!

Answer 2

I think it has to do with the fact that violet has the smallest wavelength of the visible spectra (Snell's law deals directly with the wavelength of the light), so kinda literally there's "more violet" traveling through the medium that there is, say red. Dunno if that makes sense...

Answer 3

I actually don't know if that's even a sound argument :P

Answer 4

For light in vacuum we have that:
\[c = \lambda \mu\]
\[v = \lambda' \mu'\]

And so:

\[n = \frac{ c }{ v } = \frac{ \lambda \mu }{ \lambda ' \mu' }\]

Assuming that the frequency of a wave is not affected by refraction:

\[n = \frac{ \lambda }{ \lambda ' }\]

Answer 5

I guess the question is: What makes n increase with lower lambdas? i.e. What happens to lambda prime?