find the derivative of
f(x)= sqrt(4-x^2)

Question

find the derivative of
f(x)= sqrt(4-x^2)

anonymous · Answer

(4-x^2)^1/2
1/2(4-x^2)^-1/2
1/2sqrt(4-x^2) * (-2)

anonymous · Answer

sorry , it's * (-2x) ^^

haseeb96 · Answer

f(x)=sqrt(4-x^2)
differentiate w.r.t. x 
df(x)\dx=d{sqrt4-x^2}\dx
            =(1)(4-x^2)\2 * 0 - 2x
            = (4-x^2)(-2x)\2
            = -4x + 2x^3\2
  df(x)\dx          = 2x^3-4x\2 
this is the answer

anonymous · Answer

@Haseeb96 why did you multiple the df(x)/dx by df(x)?

anonymous · Answer

I have a question if you have two inequalities and one is a dotted line on the y value of -2 and the other is a solid line is on the .5 x value  and the shaded region is quadrant one and part of quadrant four would the point of intersection not be a solution or be a solution. if someone could help that would be great.

ranga · Answer

f(x)= sqrt(4-x^2)
f(x) = (4 - x^2)^(1/2)
Use the power rule and then the chain rule.
f'(x) = 1/2 * (4 - x^2)^(-1/2) * (-2x)
       = -x * (4 - x^2)^(-1/2)  = -x / (4 - x^2)^(1/2) = $$\Large \frac{ -x }{ \sqrt{4 - x^2}}$$