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Physics 17 Online
OpenStudy (samigupta8):

all the particles of a body are situated at a distance R from the origin.The distance of the centre of mass of the body from the origin is a.=R B.<=R C.>=R D.>R

OpenStudy (samigupta8):

@oksuz_ @oOKawaiiOo @petiteme @pretty27 PLS..HLP GUYS..

OpenStudy (samigupta8):

@Preetha @ryanvarghese12790 @help123please. @firefox @GTXMUQSIT @aaronq pls..hlp

OpenStudy (anonymous):

OpenStudy (gtxmuqsit):

It's C.

OpenStudy (anonymous):

do u understand

OpenStudy (anonymous):

<=r

OpenStudy (gtxmuqsit):

oops sory by mistake it's B yeah

OpenStudy (samigupta8):

HOW

OpenStudy (gtxmuqsit):

see qts 5 on page 5 I hope you understand hindi I don't know hindi so I have translated it then tried to understand it.

OpenStudy (samigupta8):

yaa it's ryt bt where is the solution to it it's not given anywhere

OpenStudy (anonymous):

I have given you the answer B). <=R

OpenStudy (anonymous):

Here is the answer

OpenStudy (vincent-lyon.fr):

It is just a generalisation of triangle inequality: http://en.wikipedia.org/wiki/Triangle_inequality Since by definition \(M\,\vec{OC}= \sum_i m_i\,\vec{OM_i}\) , then \(M\,{OC} \leq \sum_i m_i\,OM_i=\sum_i m_i\,R=(\sum_i m_i)\,R=M\,R\) Then: \(OC \leq R\)

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