all the particles of a body are situated at a distance R from the origin.The distance of the centre of mass of the body from the origin is
a.=R
B.<=R
C.>=R
D.>R
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OpenStudy (anonymous):
<=r
OpenStudy (gtxmuqsit):
oops sory by mistake it's B yeah
OpenStudy (samigupta8):
HOW
OpenStudy (gtxmuqsit):
see qts 5 on page 5 I hope you understand hindi I don't know hindi so I have translated it then tried to understand it.
OpenStudy (samigupta8):
yaa it's ryt bt where is the solution to it it's not given anywhere
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OpenStudy (anonymous):
I have given you the answer
B). <=R
OpenStudy (anonymous):
Here is the answer
OpenStudy (vincent-lyon.fr):
It is just a generalisation of triangle inequality:
http://en.wikipedia.org/wiki/Triangle_inequality
Since by definition \(M\,\vec{OC}= \sum_i m_i\,\vec{OM_i}\) , then
\(M\,{OC} \leq \sum_i m_i\,OM_i=\sum_i m_i\,R=(\sum_i m_i)\,R=M\,R\)
Then: \(OC \leq R\)