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Solve the following equation.
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For the domain \[0 \le x \le 2\pi \]Equation: \[\sin (x- \pi) = 1\]
x-pi represents the angle for which the sin of that angle is 1. Where is the sin equal to 1?
@rach_ell
90 degrees?
Yes, that is written as pi/2 radians. so we want that x - pi = pi/2
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because when x - pi = pi/2, then sin(pi/2) = 1.
Ohh, so 3pi/2 would be the answer?
Yes. And it checks...put in 3pi/2 for x in the original equation.
sin (3pi/2 - pi) = 1 sin (pi/2) = 1 1 = 1 It checks.
Okay, thank you!
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