Question

Integrate 60/(3x-1)^.5

Answer 1

is the exponent is 0.5?

Answer 2

Yessir

Answer 3

u can try to change 0.5 into 1/2
then make it as radical or square root

Answer 4

use the substitution
u= 3x-1
then du =... ?

Answer 5

sir can u tell me the answer to this prob? i am not sure with my answer.

Answer 6

sorry dear, this is not an answering site, it is learning/studying site.
so if you want to learn how to do it, then we can proceed.
but since you have tried it, can you show your steps ?
i'll help you find the error if there is any.

Answer 7

oh ok w8

Answer 8

i use the formula of \[\int\limits_{?}^{?}\frac{ 1 }{ u } du = \ln u + c\]

Answer 9

you won't need that formula

Answer 10

what you got after plugging in u = 3x-1 ?

Answer 11

and what you get as du = ... ?

Answer 12

is it possible to use that formula sir?
my du is \[\frac{ 1 }{ 2\sqrt{3x-1} }\]

Answer 13

actually u was 3x-1 , not sqrt 3x-1

so,
u =3x-1
gives
du = 3dx
makes sense ?

Answer 14

and no, we don;t need log formula for this problem

Answer 15

so we can simplify it into \[\int\limits_{?}^{?}\frac{ 1 }{ u ^{\frac{ 1 }{ 2 }} }\] ?

Answer 16

yes, don't forget about the constants
60 and 3

Answer 17

du = 3dx
so
dx = du/3
so we have
60/3 outside that integral

Answer 18

yup, but im still confused on 1/u

Answer 19

and for that integral you can directly use the formula for integral of x^n
as
1/u^1/2 is just u^-1/2

Answer 20

sir is the answer is \[40\sqrt{3x-1}+c\] ?

Answer 21

i never thought that - exponent can be solved in the normal process.
T_T

Answer 22

yes, that answer is correct :)
good!

Answer 23

thank you very much sir. God bless po. :))

Answer 24

you're welcome ^_^
God bless you too :)