Question

find the point of inflection of

(2x)/(x^2-1)

Answer 1

Start by finding the second derivative of the function.

Answer 2

y''=(-4x)(x^2-1)-2(2x)(-2x^2-2)/(x^2-1)^3

Answer 3

Steps to find point of infection

Step 1 - find second derivative,
Step 2 - find when second derivative is = 0 or undefined
Step 3 - check if they are in the domain
Step 4 -make a table to see if the transition form + to - for points around it.

Answer 4

@NastassjaK
You may want to follow what @mebs has outlined in the steps.

Answer 5

how do you find where it is 0?

Answer 6

Where the numerator of the fraction is 0.

Answer 7

It is undefined where the denominator is zero.

Answer 8

simplify the numerator by distributing it becomes

\[\frac{-8x^3 -8x + 8x^3 + 8x}{(x^2 -1)^3}\]


simplify it... and you find the value of x that makes the numerator zero, this is the point of inflection.

Answer 9

substitute your x value into the original value to find the value of y in the ordered paia and you'll have the point

Answer 10

the bottom if you simplify it's odd so make that 0

x = 1 x = -1 and then check it with...