Question

Each year members of the school athletic department hold a fish fry to raise money for the program. They must sell tickets to the event at a price that will earn them more money than the cost of food.

Here's a formula for this scenario:
p=n(d-c)

p = Total profit made from the event
n = Number of tickets sold
d = Price charged for each dinner
c = Cost for food per plate

Rewrite the formula to determine the number of tickets they need sell.

Answer 1

\[n=\frac{ p }{ d-c }\]

Answer 2

Thanks so much :D.

Answer 3

You need to get n on it's own side of the equation as it wants a formula to determine n. It is easier to determine n when it's on its own.

So you can do what @math&ing001 said and then drag that (d-c) to the other side. But since it says they want to earn MORE money than the cost of food, it should probably become an inequality;

\[n > p/(d-c)\]

Answer 4

You're welcome :)