Use your graphing calculator to find all degree solutions in the interval 0° ≤ x < 360° for the following equation. (Enter your answers as a comma-separated list.) cos 3x = sqrt2/2 battery on my graphing calculator died, can anyone help?
well if you have some graphing software just graph y = cos(3x) and y = sqrt2/2 and find the points where they intersect this is where the 2 curves are equal.
Don't have any access to anything that can graph atm..
well you ahve the net, so try wolfram alpha or fooplot
Is it possible to do this without a graphing calculator?
sure... if you use \[\cos(3x) = \frac{\sqrt{2}}{2}\] this is an exact value... 45 degrees so \[3x = \cos^{-1} \frac{\sqrt{2}}{2}\] or 3x = 45 so x = 15 degrees well to make it easy here is a graph showing points of intersection hope it helps
oops sorry, just realised the graph is in radians.... so start at 15 and then just keep adding 90 degrees... to the previous...
I've gotten as far as 3x=45, x=15 degrees but I don't think simply adding 90 degrees gets me the answers I need. If cos 3x=sqrt3/2=10, 110, 130,230,250,350 degrees which doesn't have any patterns such as adding 90 degrees to previous
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