Question

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Answer 1

hmmm, the quotient will be that part without the remainder attached to it ...

can you find the remainder like we did last time? x+1 = 0 when x=-1, so find the value of the expression when x=-1

Answer 2

P(x) = (x+1) Q(x) + R

to find R, we need to zero out the other part ... x+1 = 0 when x=-1

P(-1) = (-1+1) Q(-1) + R

P(-1) = R, we can then determine when option has the R parts attached to see the Q(x) that we are looking for

Answer 3

... P(-1) = 0 so we cant deduce an option from that :/

it has to start with a 2x^2 and end with a +3 then which they both do ...

Answer 4

try multiplying the first option by (x+1) ...

(2x^2+2x+3)(x+1)

if we get the expression then we can pick that one, if not, then its the second one

Answer 5

2x^3 +2x^2 +3x
2x^2 +2x +3
-------------------
4x^2 is not in the original so we can ignore this one

Answer 6

2x^3 -2x^2 +3x
2x^2 -2x +3
-------------------
0x^2 +x

thats got all the right parts

Answer 7

id go with B yes