Question

Can any one plz help me? I have to raise my grade before tonight and I have no idea how to do this stuff! O.o yes Ill give you a medal

Answer 1

you would need to have some idea as to what to do ....

Answer 2

I pretty much just need answers cuz I don't want to get withdrawn from my class for the second time @amistre64

Answer 3

yeah, the thing is giving out just the answers would go against the intent of this site. The aim of this site is to teach, not to give out answers.

Answer 4

if you had some idea as to what to do, we could help guide you along the way ... iron out the rough areas. But without some notion as to what to do its just too much to deal with in such a short amount of time. Good luck tho

Answer 5

Rough guideline, quadratic formula is your friend!

Answer 6

what is the quadratic formula? maybe that will help me figure it out more @austinL

Answer 7

like how do you find the quadratic form of the first problem?

Answer 8

A quadratic equation is in the form,

\(ax^2+bx+c=0\)

You can solve for x using the quadratic formula,

\(\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

Answer 9

how do you know what x a b and c are?

Answer 10

\(12x^2+5x+7=0\)

a=12
b=5
c=7

make sense?

Answer 11

so it just goes in order? like the first number would be A and so on? and then what is x? sorry, math is not my area of knowledge

Answer 12

You solve for x using the quadratic formula.

Answer 13

ohhhhhh ok ok I gotchya, thanks that helped some

Answer 14

@austinL ok so how would I turn x2 + 4x = -15 quadratic?

Answer 15

Can you see a way to make it fit the form above?

Answer 16

yea but idk how to make it look like that, like which one is a b or c

Answer 17

You need to get it so that the far right is a zero, how would you do this?

Answer 18

that's my point, idk how to do that

Answer 19

add 15 to both sides....

Answer 20

ok so I got x2 + 4x + 15 = 0
so now the x2 is A
4x is B
and 15 is C?

Answer 21

No, the letters are just the coefficients in front of them.

Answer 22

how the heck do you finish that problem then, im getting so confused here

Answer 23

Here I will make an example for you, and I will solve it out. Then you can hopefully solve yours by following the example.

Answer 24

ok thx

Answer 25

Let's say we have,

\(2x^2-2x-4=0\)

\(a=2\\
b=-2\\
c=-4\)

\(\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)

\(\displaystyle x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(-4)}}{2(2)}\)


\(\displaystyle x=\frac{2\pm\sqrt{36}}{4}\)

\(\displaystyle x=\frac{2\pm6}{4}=\frac{8}{4}~OR~\frac{-4}{4}\)


Which means,

x=2 and x=-1

Make sense?

Answer 26

that was a good try; but as i mentioned "without some notion as to what to do its just too much to deal with in such a short amount of time". The tools needed to work these have to be developed with a ton of practice, and there simply was not enough time to accomplish that.