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The derivative of a continuous function is f′(x) = 2x(x − 1)^3 Find the open intervals on which f is increasing A)None of these B)On (−∞, 0) and on (1, ∞) C) On (−∞, 0) D) On (0, 1) E) On (−1, 0)
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increasing and decreasing - first derivative concave up concave down - second derivative you need to graph the function and determine where it is increasing
f′(x) = 2x(x − 1)^3 If f'(x) > 0 in an interval, f(x) is increasing in that interval. When is f′(x) = 2x(x − 1)^3 > 0 ?
first we need to find all values of x that equal to 0. then we create a sign chart so the equation is 0 when x = 0 and 1 so pick any point within those areas|dw:1384210880637:dw|
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