Tan^2×sin^2×=tan^2×-sin^2 ×

Question

anonymous · Answer

$$Tan^2×Sin^2×=Tan^2×-Sin^2 ×$$
$$Tan^2x=\frac{Sin^2x}{Cos^2x}$$
substitute,
$$Tan^2x  \times Sin^2x=Tan^2x-Sin^2x --->\frac{Sin^2x}{Cos^2x}\times Sin^2x=\frac{Sin^2x}{Cos^2x}-Sin^2x$$
$$\frac{Sin^4x}{Cos^2x}=\frac{Sin^2x}{Cos^2x}-SIn^2x$$
$$\frac{Sin^4x}{Cos^2x}=\frac{Sin^2x}{Cos^2x}-\frac{Sin^2x}{1}$$
$$\frac{Sin^4x}{Cos^2x}=\frac{Sin^2x}{Cos^2x}-\frac{Sin^2x \times Cos^2x}{Cos^2x}$$
$$\frac{Sin^4x}{Cos^2x}=\frac{Sin^2x-Sin^2x \times Cos^2x}{Cos^2x}$$
$$\frac{Sin^4x}{Cos^2x}=\frac{Sin^2x(1-Cos^2x)}{Cos^2x}$$
$$\frac{Sin^4x}{Cos^2x}=\frac{Sin^2x(Sin^2x)}{Cos^2x}$$
$$\frac{Sin^4x}{Cos^2x}=\frac{Sin^4x}{Cos^2x}$$
$$Identity$$