Question

Calc help plzzz

Answer 1

Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function h(t) = 6 + 37t – 16t2, where h is in feet and t is in seconds. At what time t does the ball stop going up and start returning to earth?
(Points : 1)
1.42341 seconds
0.04684 seconds
2.46551 seconds
1.15625 seconds
4.33232 seconds

Answer 2

So this equation gives you the height of the ball in regards to the time.
If you differentiate that, you will get how fast the height of the ball is changing, which will be 0 at its peak height (the split second where the ball stops going up and starts going down, its height stays the same)
So first differentiate your h(t)...

Answer 3

yes

Answer 4

Well, go on, differentiate the formula :)