Question

find dy/dx of y = (2x^7-x^2) (x-1/x+1)

Answer 1

u have
\[ \large (2x^7-x^2)\cdot\left(\frac{x-1}{x+1}\right) \]
do u know which rules to use?

Answer 2

umm do you use the Quotient rule on the (x-1/x+1) right?

Answer 3

then product rule?

Answer 4

actually, first the product rule and then the quotient rule

Answer 5

u have
\[\large (AB)'=A'B+AB' \]
but B is quotient so
\[\large B=\frac{C}{D} \]
then
\[\large B'=\frac{C'D-CD'}{D^2} \]
got it?

Answer 6

kinda..

Answer 7

try it!

Answer 8

post your solution, so we can help you better

Answer 9

hmm can you explain the above thing better ^

Answer 10

your function has two "main" operations, one multiplication and one division. right?

these tell which of the rules of differentiation to use.

now since multiplication comes first (is to the left of the division) u apply this rule first.

ok?

Answer 11

u have
\[\large y=(2x^7-x^2)\cdot\left(\frac{x-1}{x+1}\right) \]
so
\[\large y'=(2x^7-x^2)'\left(\frac{x-1}{x+1}\right)+(2x^7-x^2)
\left(\frac{x-1}{x+1}\right)' \]
ok?

Answer 12

ohhh okay i see

Answer 13

try it! u have to try.

Answer 14

okay so do i do the Quotient rule now?

Answer 15

u have two derivatives, for the second yes, u have to do the quotient rule