PART ONE: Your friend comes up with a design for the perfect garden and says to create it you need an area of 35 square feet. if this is your ideal garden, what would be the measurements of your width and length. PART TWO: during the winter months, MR Dugan assigns another set of students to design a rectangular tent to cover your garden. the volume of their tent was represented by 2x^2-5x^2+3x. the garden still had the original length and width from the previous example, what was the measure of height in terms of x
height = Volume/(lw)
you have to use l and w from part (a)
If you say so, as I didnt do part (a)
well i know you have to do w^2= 35 but is that a quadratic equation?
for part one
you said that you only need a hand with part (b). II stopped helping others to help you with part (b). I cant do part (a) now.
someone questioned my part a but i really need help with part b
Ok.. I will see this problem in 2 min. Just hang on.
ok thank youu!!
OK. I'm back. Let me do both parts.
great! thank youu
In part (a) ...if the area is 35 square feet, the length could be 7 ft and the width could be 5 ft.
agree? becuase 7 ft x 5 ft = 35 square feet
to solve the problem my teacher said you need to use a quadratic equation
Forgive me, but if you read the problem for part(a), it asks you to find a length and width so that the area is 35 square feet. So I chose length to be 7 feet and width to be 5 feet. I don't know what your teacher is referring to. I'm answering the part(a) as posted above. No need for any quadratic equation. It asks for an ideal length and width so that the area is 35 sq ft. I can choose whatever numbers I want, and 7 and 5 are nice numbers.
ok i understand
Take a moment and read part (a). It allows me to choose ideal length and width.
yes, ok i get it noww
it makes sense
So, honestly, I dont begin to understand why your teacher brings up quadratic equation. Unless the teacher was talking about a different problem.
For part (b). You want to find the height of the tent, given the volume, and to use length and width from part(a).
So, as I wrote earlier, Volume = length x width x height OR V = lwh we want h, the height. So we divide both sides of the equation by lw. so the height, h = v/(lw) so h = (2x^2 - 5x^2 + 3x)/35 I believe there's an error in the volume...because the volume wouldnt have 2x^2 - 5x^2...it would have an x^3 ...but above is the final answer for the height....assuming the volume was typed correctly.
@santashelper Makes sense?
Just make sure that the entire question was typed correctly. I answered the question purely based on what was typed in this post above.
i copied and pasted the question
thats cool; but the volume given is kinda weird volume.
I believe that there is an error in the book itself; they probably meant to put an x^3 or something with an x^3. Finally, I dont really like this question, as part(b) serves no purpose in giving the volume algebraically, as it doesn't ask the student to do anything with that volume expression.
thank you for your time and help!!!
No proble. Welcome. And ask your teacher about that weird volume...I've never seen a volume expressed with x^2 twice in one expression. Take care and good night.
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