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Find all real zeroes of the function. g(x)=2x^3+4x^2-2x-4
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set it equal to 0 and factor out gcf if any
1,2,4,8 then what?
wats 1,2,4,8 ?
to find zeroes, you need to solve below :- 2x^3+4x^2-2x-4 = 0
i know but how do i soolve it?
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factor 2 first
\(2x^3+4x^2-2x-4 = 0\) \(2(x^3+2x^2-x-2) = 0\) \(x^3+2x^2-x-2 = 0\)
Look at this cubic, by inspection 1 is a zero of this equation (why ? )
so now i use synthetic division
Yup !
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okk so i used it and i got a zero by using 1 but then i dont know how to find thezeroes
wats the depressed equation you got after synthetic division ?
|dw:1384228894379:dw|
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